Calculus - Limits.........

1

is the ans 0

62

y!!

this is not that straight forward.. (sorry if i am already making a wrong assumption!)

I thnk this question needs a few things

Hint: check if derivative of sinx/√cosx near zero

1

is ans 1

1

i think ans would be 1

1

applying l hospital rule inside the box

we get the reduced expression as 1/cosx

now if x->0-
then it is 1/cos(-h)=1 hence the expression =1
otherwise also it is 1/cosh=1

hence answer =1

Limits.........