limits

A_n+1=(A_n+(a/A_n))/2 , where A₁>0,a>0.

Find Lim_{nâ†’âˆž}A_n

2 Answers

IF the limit exists.. A_n = A_n+1 = L ( let )

Thus, if the limit exists, it will imply that

x=(x+a/x)/2

x=a/x

x=√a

I tried to use excel to confirm my result but surpringly I am not getting the same answer :(

341

Hari Shankar ·2009-09-08 02:17:21

You should, because this is one of the algorithms used to find out the square root of a number

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