e2. I did this some time before
2 Answers
Unicorn--- Extinct!!
·2009-10-05 21:54:08
This can be written as
[{(n+1)(n+1/2)...(n+1/2n-1)}/nn]n
=[(1+1/n)(1+1/2n).....(1+1/2n-1n)]n (1∞ form)
=e1.e1/2e1/4.....e1/2n-1....∞
=e2