3 1
- Himanshu Giria 3->A(1)
- Anindita Roy 3) does not exist as lhl is not equal to rhl
- Raunaq Saha Ya I got the answer of 3 . It will be (d) In the shastras answer of 1 is given as (b)log1
Q1:
a)-1
b)loge1
c)1
d)none
q2:
a)12sin3a
b)12cosec2a
c)sin3a
d)cosec3a
q3:
a)1
b)-1
c)0
d)none
q4:if 0<x<y then
a)e
b)x
c)y
d)none
q5:
a)1
b)sinxx
c)xsinx
d)none
first one
log(sinx)/1/x
Applying L'Hospital
cotx/(-1/x2)=-x2/tanx=-(x)(x/tanx)=0 as x->0
For second one i m getting the (1-cosa)/(1-cota)
I think there's a mistake in the question..
it should be
lim (x->a)(cosx-cosa)/(cotx-cota)
Sir how does the first one exist ?
M not understanding how lhl exists .. log of -ve is not defined . So sir where m i wrong ?
3 1