1wats d diff in
removable& irremovable discontinuity
Iff(x)=\frac{xln(1+sinx)}{ln(1+sin^{2}x)},x\neq 0
= 0, x = 0
Then the function
(A) has an irremovable discontinuity at x = 0
(B) has a removable discontinuity at x = 0
(C) is continuous but not differentiable at x = 0
(D) is differentiable at x = 0
-
UP 0 DOWN 0 0 14
14 Answers
62if the limit exists and is finite at that point then it is said to be removable discontinuity!
it is like saying that if by changing the value of f at that point you can make the function continuous..
Like f(x)=[sin x]
has removable discontinuities
21warts da ans??
I f(x)= 1 as lim x--->0
so i say B......
ne1 gettin da asame ans
21kyun?
matlab wat u dint get ??
did u get this ? f(x)= 1 as lim x--->0
1\lim_{0}xln(1+sinx)/ln(1+sin^2x) =\lim_{0}[ln(1+sinx)/sinx]*(x/sinx)/[ln(1+sin^2x)/sin^2x)] nw \lim_{0} ln(1+x)/x=1 so ur f(x) as limx -->0 is 1 :)