3
lh works good
1) \lim_{x\rightarrow 0} (\frac{1}{sinx}-\frac{1}{x})
2)\lim_{n\rightarrow \propto } \frac{4^{n}+3^{n}}{4^{n}-3^{n}}
3) \lim_{x\rightarrow 0} \frac{\tan^{-1}x-\sin^{-1} x }{x^{3}} ,, LH not working
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8 Answers
Anirudh Kumar
·2010-06-29 04:35:55
in the 1 ques
take the LCM and apply LH rule twice
lim x-sinx/xsinx
= lim 1-cosx/(sinx+xcosx)
= lim sinx / cosx+ cosx + xsinx
= 0
qwerty
·2010-06-29 09:54:32
ya -1/2 is d ans
btw dere is 1 more method
covert sin-1x into tan-1(something)
and then convert tan-1x - tan-1(something ) = tan-1(again something )
then use lim y ->0 tan-1y / y = 1
souvikbhanja
·2010-07-05 16:29:57
In 3 use da inverse series................
U ll gt da ans in da 2nd lyn.............