Maths ques

Q1)

The function f : R → R defined by
f(x)=x3+x2
is
(a) one to one
(b) onto
(c) one to one and onto
(d) neither one to one nor onto

Q2)

The function
f(x)= x2/|x| if x is not = 0
= 0 if x=0

(a) is not continuous at x = 0
(b) continuous at x = 0, but not differentiable
(c) differentiable once, but not twice
(d) differentiable infinitely many times

Q3)

The differential equation

(a) degree 1 and order 2
(b) degree 2 and order 1
(c) degree 1 and order 1
(d) degree 2 and order 2

Q4)

Let A, B and C be 3 matrices of order n X n such that ABC = I, where I is the identity matrix of order n, then
(a) A, B and C are always invertible
(b) A, B and C are not necessarily invertible
(c) B is invertible
(d) A is always invertible

14 Answers

23
qwerty ·

wats the function ?

1
lalit ·

where is ur function arka

1
Arka Halder ·

edited the post everybody.plz see now.

1
soumyadeep sanyal ·

2)b
3)a

1
soumyadeep sanyal ·

think the ans to 1 is c

1
ABHI ·

1 C
2 D
3 B

1
Arka Halder ·

shouldnt 3 be a abhirup?
2nd order of derivative is max and the highest power of that is 1.

1
ABHI ·

ya ya sorry ....3 a.....confused that thing....ya 3 A

1
ABHI ·

∫1-1x21+1xdx (limits from 1/2 to 2)
=∫dzz (limits from 5/2 to 5/2) = 0......where z=1+1x
whats the flaw in dis 1....first confirm yourself that there is a flaw as the integration of the original function cannot be 0

1
utd4ever ·

answers are
1b
2b
3b
4a
are they correct

1
lalit ·

1-c
2-b

1
Anirudh Kumar ·

ans 1)
function has two roots 0 and -1 . thus it is not one-to one . but ti's range is R .
thus is onto .
Option B

1
pgoklani ·

3)as far as 3 question is concerned the option wud be (a)
2)ans of second one wud be(b) as

{-x,x<0
f(x)={0,x=0
{x,x>0
so ans (b)
1)ans of (1) cannot be (c) as if f(xi)=f(x2)
means x1sq+x2sq-x1-x2+x1x2=0
not x1=x2

1
ronak agarwal ·

ans to ques 1 is (b)
ques 2 is (b)
ques 3 is (a)

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