find the minimum value of (3sinx-4cosx-10) * (3sinx+4cosx-10)
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2 Answers
Asish Mahapatra
·2010-03-11 01:54:17
writing as:
(9sin2x+100-60sinx) - 16cos2x
=> 25sin2x - 60sinx + 84
min. when sinx=1.. (1 is closer to 60/50)
=> min value = 49
Manmay kumar Mohanty
·2010-03-11 01:56:55
I GOT THE SAME YAAR.
BUT WAS CONFUSED IF sin x = 60/50 as it is not possible