106maybe uve to take differnt values of x and see whether it passes thru those pts
f(x) = e2x. Then the normal to the curve f(x) passes through
(a) (0,1)
(b) (lne, e2)
(c) (1/2, e)
(d) (-1/4, 1/√e)
-
UP 0 DOWN 0 0 10
10 Answers
24f'(x)=m=2e2x
slope normal=-e-2x/2=m1
eqn normal
Y-y=m1(X-x)
but its not given norma at which point ....so it cnat be solved,,,
maybe incomplete ques
106
11What abt the graph???
we can do it with the help of graphs??? not sure.
24but at what point is normal ??
we need to know that..so that we can find atleast slope...
3actually the qn says we have to verify the pts which are on the curve,bcos we can always draw a normal that passes thru a given pt.So need to confuse that we havent given the relation abt the normal,may be this wont strike in exam hall.
24ok we can verify for those points which lie on curve..but there maybe some points which dont lie on curve but still lie on some normal for the curve
3yeah u r rite,but the qn doesnt ask this,it asks that we have to the pt at which the normal meet the curve again,so obviously the pt shud lie on the curve.
1actually the question should be
f(x) = e2x , then the curve y= f(x) passes through :
then the answer can be abcd. [3]