nice integral..

∫log(1+x)/1+x2dx
limits r 0 to pi/4

4 Answers

1
" ____________ ·

put x= tanθ

dx = sec2θ

1 + x2 = sec2θ

integral reduces to ∫log ( 1 + tanθ) dθ

i think this cannot be solved .

u forgot to tell the limits

39
Pritish Chakraborty ·

On solving on my own by parts I'm getting 0 = 0...waah!

49
Subhomoy Bakshi ·

so that shows that it is a right question...LOL...[3][3][3]

11
Devil ·

The substitution x=tan\alpha seems to work.

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