1But its answer is 1/10pie
Q:- An inverted cone has a depth of 40cm and a base of radius 5cm.Water is poured into it at a rate of 1.5 cubic centimetres per minute.Find the rate at which the level of water in the cone is rising when the depth is 4cm.
-
UP 0 DOWN 0 0 3
3 Answers
1V=\frac{1}{3}\pi r^{2}h
\frac{dV}{dt}=\frac{d}{dt}\left(\frac{1}{3} \left(\frac{h}{8} \right)^{2}h\right)
\frac{dV}{dt}=\frac{d}{dt}\left(\frac{1}{192}\pi h^{3} \right)
\frac{dV}{dt}=\frac{1}{192}\pi 3h^{2}\frac{dh}{dt}
1.5=\frac{1}{64}\pi 16\frac{dh}{dt}
dhdt = 1.5 x 4\pi
dhdt = \frac{6}{\pi }
pehle ye kiya tha sayad usme depth 10 cm tha baki sab data same hai isliye check kar.Thik hai to yahi ans. hoga anhin to 38pihoga
1YAAR PLEASE CONFIRM THE DATA OF THE QUESTION ONCE AGAIN.