1V=\frac{1}{3}\pi r^{2}h
\frac{dV}{dt}=\frac{d}{dt}\left(\frac{1}{3} \left(\frac{h}{8} \right)^{2}h\right)
\frac{dV}{dt}=\frac{d}{dt}\left(\frac{1}{192}\pi h^{3} \right)
\frac{dV}{dt}=\frac{1}{192}\pi 3h^{2}\frac{dh}{dt}
1.5=\frac{1}{64}\pi 16\frac{dh}{dt}
dhdt = 1.5 x 4\pi
dhdt = \frac{6}{\pi }
pehle ye kiya tha sayad usme depth 10 cm tha baki sab data same hai isliye check kar.Thik hai to yahi ans. hoga anhin to 38pihoga