62
Lokesh Verma
·2008-11-05 07:59:38
hmm.. interesting...
i get ur question.. it is very thought provoking... i will post somting may be in a bit.. cos i need to be convinced about my arguments first :)
62
Lokesh Verma
·2008-11-05 08:05:31
see my first "guess"
is that the concept of repeated roots is only for polynomials...
sin is not a polynomial in that sense... of course taylor's expansion does make everythign close to a polynomial...
33
Abhishek Priyam
·2008-11-05 08:09:47
Don't know sir said its related to degree of tangency or something like that......
x3 has degree of tangency 3 at x=0....
as up to second derivative it is zero at x=0;
this is true for sinx also at pi/2 cosx=0...
so should be two solns...
but he said its about convention so sinx =1 has one soln....
i think....
62
Lokesh Verma
·2008-11-05 08:15:41
hmm.. i guess ur sir has some point..
but i wud be interested in knowing the degree of tangency.. cos i never heard of something like this!
33
Abhishek Priyam
·2008-11-05 08:36:46
i got something at (in eng this time)
http://books.google.co.in/books?id=0ZwmLz_UTYoC&pg=PA60&dq="degree+of+tangency"#PPA60,M1
also
...
http://books.google.co.in/books?ct=result&q="degree+of+tangency"&btnG=Search+Books
1
voldy
·2008-12-21 18:20:40
I didn't understand what the Q meant?
1
voldy
·2008-12-21 18:21:45
do u mean y sinx attains 1 at only one value in the given regoin ?
1
Honey Arora
·2008-12-21 21:25:30
i think no. of roots are defined by power of the polynomial.............as xn has n roots similarly x3 has 3 roots
bt if we take sin(x)=1
=> sin-1(1)=x ,so here also it depends upon power of x and second thing is interval in which it lies.............
i don't know hw right i m..........
341
Hari Shankar
·2008-12-21 22:02:59
The fundamental theorem of algebra is related to polynomials.
It says that the polynomial of degree n
aoz^n+a1z^{n-1}+...+an = 0
has at least one root in the field of complex numbers
From factor theorem we deduce that it has exactly n roots counting repeated roots.
sine is not regarded as a polynomial and hence the theorem doesnt apply
39
Dr.House
·2009-10-07 02:51:51
i was not fully satisfied with the discussion, so posted in mathlinks again...
u can see the explanation here
http://www.mathlinks.ro/viewtopic.php?t=304586
3
msp
·2009-10-07 02:59:45
well i have read something abt repeated roots.
if f(∂)=0 and f'(∂)=0 then ∂ is said to be a repeated root of f(x)