Please Do this integration for me!

\int \left(tan^{-1}x \right)^{2}dx

11 Answers

1
Vinay Arya ·

I=∫(tan-1x)2dx
Integration by parts
I=x(tan-1)2-∫2xtan-1x1+x2dx
I'=∫2xtan-1x1+x2dx
tan-1x=t
dx=(1+x2)dt
I'=2∫t tant dt
I'=2tlog!sect!-2∫log!sect!dt
I'=2tlog!sect!-2tlog!sect!-∫t tantdt
I'=-4tlog!sect!-I'/2
I'=8tlog!sect!/3
I=x(tan-1x)2-8tlog!sect!/3 +C

1
swordfish ·

@ Vinay
which software do you use for writing the HTML math?

1
Vinay Arya ·

I do not use any software.Whatever facility is given on this forum I use it.

1
Ricky ·

Vinay , in line no. 9 , you get

I ' = 2 t log ( sec t ) - 2 t log ( sec t ) + I ' ........................ : )

You have part integrated taking one function , then again part integrated taking the other function , which leaves you at -

I ' = I '

Actually , this is an un - integrable function . You cannot find its antiderivative in terms of known functions . The actual answer may be verified at -

http://integrals.wolfram.com/index.jsp?expr=%7BArcTan%5Bx%5D%7D%5E2&random=false

49
Subhomoy Bakshi ·

@Soumya: This is an AISSCE question! :P
:P

This is then a sure boomerang! must be awarding free +6 to all??

39
Pritish Chakraborty ·

This came in the boards some years back and if I remember correctly, there was controversy regarding it. Surely +6 to all.

21
Shubhodip ·

I wonder how wolfram does integrations like that!!!!

1
swordfish ·

Damn!! I never saw the fraction button.

1
anishvarsha iska ·

use the following word to solve by parts
ILATE

I - Inverse trignometric functions
L - Logarithmic functions
A - Arithmatics
T - Trignometric functions
E - Exponential functions

take the above functions values by u

71
Vivek @ Born this Way ·

@anish.. Yeah that is okay, But it won't work here.. You can even try ∫x tanx dx

1
jee12 ·

is it not possible to integrate this function ???

∫ log (cosx) dx

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