Yaar, its not visible.
7 Answers
Manmay kumar Mohanty
·2010-05-05 23:39:36
anirban please see this thread
http://targetiit.com/iit-jee-forum/posts/latex-not-workin-15025.html
that might help u to latexify ur question properly :)
Devil
·2010-05-06 00:08:12
The qsn:- From ISI - Let f(x) be a continuous function whose first and 2nd derivatives are continuous in [0,2π] and f''(x)≥0 for all xin the given interval.
Show that \int_{0}^{2\pi }{f(x)cosxdx\ge 0 }.
Solution
f'(x)-f'(0)\ge 0
So \int_{0}^{x}{f'(x)dx}\ge \int_{0}^{x}{f'(0)dx}
From which we have f(x)\ge xf'(0)+f(0)
Now f(x)cosxdx\ge xf'(0)cosxdx+f(0)cosxdx
Thus \int_{0}^{2\pi}{f(x)cosxdx} \ge \int_{0}^{2\pi}{xf'(0)cosxdx}+\int_{0}^{2\pi}{f(0)cosxdx}\ge 0.