pls koi jaldi banao!!!

see, √1-ksin²x = √k √1/k - sin²x

now in √1/k - sin²x

1/k - sin²x >0

if K >1 => 1/k <1

sin²x ε [0,1]

=> 1/k - sin²x <0 for some x ...

this is not possible...

so 0<k<1 always..

[7]

2nd ??

ek hi toh question hai !

@mathie, how can u leave anything ?

leave it... n start trying :P

sinx bade badoan ki band baja deta hai

WHY??????????????

and sky check the ques again kahin k²to nahin hai

NO! k cant be any integer ...