Calculus - Plz help in dis Limit!!

66

kaymant ·2010-05-12 23:42:06

Probably he intended to have a minus sign in the numerator in which case the required result would be 1&ndash log y1+ log y

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Kazi Saiful Islam ·2010-05-13 00:50:42

But the ans that is GIVEN: 1

by da way,sir,hw did the ans(1-log y1+log y) come?
plz explain!!

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kamalendu ghosh ·2010-05-13 00:59:04

apply l'hostipal

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Kazi Saiful Islam ·2010-05-13 01:06:35

Even after dat,how can the ans come "1"????

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Bicchuram Aveek ·2010-05-13 01:41:17

KAJU CHECK IT :!!! THERE'S A SERIOUS TYPO HERE !!!!

look :

it's a 0/0 form so L'Hospital bhaiya comes in action !!

so
Lt. y x^y-1 - y^x log yx^x( 1+ log x)
xâ†’y

so as xâ†’y replacing x by y :

we have

y ^y - y^y log yy^y( 1+ log y)

it can only be 1 if numerator has the "+" sign.

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66

kaymant ·2010-05-13 02:05:35

@Aveek
If its a plus sign in numerator, it does not qualify for the application of L'Hospital in the first place.

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Bicchuram Aveek ·2010-05-13 09:30:29

yup ... got it....deleted #8.

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Kazi Saiful Islam ·2010-05-14 00:41:24

I am sorry!!!! the numerator is x^y-y^x & not '+'!!!

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