integration
a.secx + b.cosecx dx
sinx + cosx
limits 0 to pi/2
awkwardly enuf i am getting 0 [11]
62PHilip.. you are makign the mistake of forgetting to take the limit...
you have to integrate from a to pi/2-a
and then take limit a going to 0
1ok plz close this thread now the correct answer can be found using the method given by nishant bhaiyya above
and since my problem is actually something else altogether forget it and don't waste more time on it
hopefully i will find the "board" (read bored) method for it [6]
1ya i tried doing all this bcoz i cud not think of any simpler method but since i never saw the use of limits in ISC board ques i am begining to believe i will have to something altogether different
btw if i used this method it will satisfy me but unfortunately i will get 0 in my paper
62philip i remember the limit thing that i am talking is in CBSE too....
1can you explain a bit more celestine ?
bhaiyya but ye board ka question hai must be quite simpler
1replacing x → pi/2 -x
i get
Ï€/2
2I = (a+b)∫ (1/sinx.cosx) dx
0
is something wrong up till here [7]
1hw cn u get ans by putting sin x =t?.....thn dt will be (cos x dx) bt it is in the deno.
11Sky, not calculation mistake......it is calculus mistake [3]
