Plzzzzz help

Ques) If f1(x) = (x/2) + 10 , for all x belonging to R and defined by f n (x) = f1 { fn-1 (x)}, for all n≥2. Then show that lim n →∞ fn(x) = 20

I try to solve it this way,
f1(x) = x/2 + 10 = (x+20) /2
Similarily, f2(x)=. (x+60) /4
f3(x) = (x+140) / 8
f4(x) = (x+300) / 16
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The denominator(2,4,8,16,....) is forming a G.P of r=2
BUT STILL IN VAIN

6 Answers

11
Tush Watts ·

No takers???

1357
Manish Shankar ·

fn(x)=10+10/2+10/22+..+10/2n-1+x/2n

11
Tush Watts ·

@Manish sir
Sir Is my solution right or wrong???

1
Divesh ·

We can use here that condition ..

as the n is tending to infinity ...

f (n ) = f ( n +1 ) = f (n-1 ) .. just see if it could help .. !

1357
Manish Shankar ·

it is ofcourse right

from your solution

f1=(x+20)/2
f2=(x+60)/4=(x+80-20)/4=x/4+20-20/4
f3=(x+140)/8=(x+160-20)/8=x/8+20-20/23
f4(x)=x/24+20-20/24

Now continue from here, you will get the result

11
Tush Watts ·

@Mianish sir
Thanx a lot sir

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