practice for bitsat.....

∫(x-a)(x-b)(x-c).........(x-z)dx
is equal to
1. constant
2.5c+5d+x
3.0
4.none of these

9 Answers

1
Manmay kumar Mohanty ·

its constant
∫(x-a)(x-b)(x-c)........(x-x)(x-y)(x-z)dx
u can see (x - x) =0
hence integral is constant

1
pranav ·

its a IIT 1938 QUES ,,,,,dont u know,....ask buddidadi,,,,,,,,!

1
yes no ·

@ manmay

then answer should be " a constant" and not zero :P

21
omkar ·

why/ what are u hiding pranav??

21
omkar ·

the ans can be 0 or const ..... coz the differentiation of both 0 and const is 0.

1
Manmay kumar Mohanty ·

oops !!! galti se likh diya [3]
now edited

1
pranav ·

,,,dont u know,....ask buddidadi,,,,,,,,!

1
pranav ·

http://targetiit.com/iit-jee-forum/posts/iit-jee-1938-15958.html

1
sindhu br ·

thanks all
had doubt about whether its constant or zero :)
by the way who is this buddidadi?

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