practice for bitsat.....

IIT JEE Tutorials › Calculus questions › practice for bitsat.....

âˆ«(x-a)(x-b)(x-c).........(x-z)dx
is equal to
1. constant
2.5c+5d+x
3.0
4.none of these

#Mathematics #Calculus

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9 Answers

1

Manmay kumar Mohanty ·2010-05-07 01:50:07

its constant
âˆ«(x-a)(x-b)(x-c)........(x-x)(x-y)(x-z)dx
u can see (x - x) =0
hence integral is constant

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1

pranav ·2010-05-07 02:24:28

its a IIT 1938 QUES ,,,,,dont u know,....ask buddidadi,,,,,,,,!

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1

yes no ·2010-05-07 02:28:42

@ manmay

then answer should be " a constant" and not zero :P

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21

omkar ·2010-05-07 02:29:04

why/ what are u hiding pranav??

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21

omkar ·2010-05-07 02:30:23

the ans can be 0 or const ..... coz the differentiation of both 0 and const is 0.

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1

Manmay kumar Mohanty ·2010-05-07 02:30:35

oops !!! galti se likh diya [3]
now edited

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pranav ·2010-05-07 02:36:38

,,,dont u know,....ask buddidadi,,,,,,,,!

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1

pranav ·2010-05-07 02:37:45

http://targetiit.com/iit-jee-forum/posts/iit-jee-1938-15958.html

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1

sindhu br ·2010-05-07 03:21:31

thanks all
had doubt about whether its constant or zero :)
by the way who is this buddidadi?

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