problem

x+2|y|=3y where y=f(x),then f(x) is....
A)continuous everywhere
B)diff everywhere
C)discontinuous at x=0
D)none

5 Answers

Oh just break the fn for y>0 and <0

for y>0

y=x

now for for y<0................

now whenever y>0, x>0 and whenever y<0, x<0

So at x=0....... u can get that.....

As far as i understand, first assume yâ‰¥0 and then yâ‰¤0.

This will give u two equations of y both of which give u functions continuous everywhere.

perfect Rajat :)

it is continuous everywhere and non differentiable at x=0

yeah i've edited the mistake. Its continuous everywhere and non diff. at zero.

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