1As far as i understand, first assume y≥0 and then y≤0.
This will give u two equations of y both of which give u functions continuous everywhere.
x+2|y|=3y where y=f(x),then f(x) is....
A)continuous everywhere
B)diff everywhere
C)discontinuous at x=0
D)none
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5 Answers
33Oh just break the fn for y>0 and <0
for y>0
y=x
now for for y<0................
now whenever y>0, x>0 and whenever y<0, x<0
So at x=0....... u can get that.....
1
1it is continuous everywhere and non differentiable at x=0
1yeah i've edited the mistake. Its continuous everywhere and non diff. at zero.