FIND I
I=∫ (x2.tan-1x)/(1+x2)3/2 dx
Is it ∫(θsec3θ-θsecθ)dθ where θ=tan-1x?
the answer is
x3/3(x2+1)3/2.tan-1x + 1/3√(x2+1) - 1/9(x2+1)3/2 + c
But I'm not sure abt the soln
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