I'm thoroughly confused, eureka. I'm not able to make out what's where [7]
5 Answers
Anirudh Narayanan
·2009-01-08 06:44:08
Hari Shankar
·2009-01-08 17:36:26
Let f(x) = 0∫x etx-t2dt - ex2/40∫xe-t2/4 dt
f'(x) = ex2-x2 - et2/4 e-t2/4 = 1-1 = 0
Hence f(x) is a constant. We see that f(0) = 0
Hence f(x) = 0 for all x.
Hence 0∫x etx-t2dt - ex2/40∫xe-t2/4 dt = 0 or
0∫x etx-t2dt = ex2/40∫xe-t2/4 dt