we already know
e^{x}\geq (1+x)
s similarly we have \sqrt{e^{2x}}\geq \sqrt{(1+x)^{2}}
and hence inequality.
equality is at x=0
prove that e^{x}+\sqrt{1+e^{2x}}>(1+x)+\sqrt{2+2x+x^{2}} for x belongs to R(note its ≥ not >)
we already know
e^{x}\geq (1+x)
s similarly we have \sqrt{e^{2x}}\geq \sqrt{(1+x)^{2}}
and hence inequality.
equality is at x=0