Prove the value of integral

Prove the value of integral \int _{0}^{1} \sqrt {1+x^3} is less than √7/2

1 Answers

106

Asish Mahapatra ·2009-09-22 02:22:00

the max value of 1+x³ in the interval given is 2 (when x=1)
So the max value of the interval is âˆ«√2dx (x=0 to x=1)

So the max value of the interval is âˆš2
the min value of the interval is 1.

Obviously √7/2 > √2 So the value of the interval is less than √7/2 also

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