partial differentiation
5 Answers
substitute x = sin A and y = sin B (There is a small rider, we will chose A and B such that cosA and cosB are positive, otherwise this solution will fail!) Did u figure out why??!!
The equations get reduced to...
cos A + cos B = a (sin A - sin B)
2 cos (A+B)/2 . cos (A-B)/2 = 2 a cos (A+B)/2 . sin (A-B)/2
cos (A-B)/2 = a sin (A-B)/2 ........(1)
Thus, cot (A-B)/2 = a
A - B = 2 cot-1a
or sin-1x - sin-1y - 2 cot-1a
Differentiating above eq. w.r.t.x
1/√(1-x2) - 1/√(1-y2) dy / dx = 0
dy/dx=√(1-y2)/(1-x2)
By partial differentiation we have -:
Fx : -1√1 - x² + 0 = a(1 - 0)
And Fy : -1√1 - y² + 0 = a(0 - 1)
dydx = -FxFy
=> √1 - y²√1 - x² (by dividing above relations)
Fx means diff wrt x treating y as constant, and Fy is vice versa.