33for q1 consider one octant at a time.. in 1st x and y both postv so x+y<=1 you can plot these
x>0 y>0 and x+y<=1
similarly for 2nd quad x<0 and y>0 and -x+y<=0
similarly for 3rd and 4th quad
Q2 think for a while yourself...
Q1Graph the inequality |x|+|y|≤1
Q2)When we shift the graph of(x) through a towards left, we transform f(x) to f(x-a).Say funct be y=x.If I change it to y=(x-1). first f(2)=2, f(3)=3 f(4)=4.Now (3)=2 f(4)=3 f(2)=1.this means initially, 2 was the value for 2 but now its the value for 1(i.e 2-1).Similarly initially, 3 was the value for 3 but now its the value for 2(i.e3-1).If we do like this the graph shifts to the left.this is in complete contrast with the first statement.plzzzzzzzz explain.
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3 Answers
33
49q2:: http://www.targetiit.com/iit-jee-forum/posts/shifting-of-graph-16741.html