1) d
2)what u wanna prove by saying that
(a) lim x→a f(x) is integer
(b) lim x→a f(x) is non integer
U wanna say like a number is odd and still it is even[11]
1) If k sin2x + (1/k) cosec 2 x = 2, for all x belonging to (0, pie/2) then cos2x + 5 sinx cosx + 6 sin 2x is equals to
(a) (k2+5k+6) / k2
(b) (k2-5k+6) / k2
(c)6
(d) none of these
choose the correct alternative
2) If lim x→a f(x) = lim x→a [f(x)] (where[.] denotes the greatest integral function) and f(x) is non constant continous function, then show that
(a) lim x→a f(x) is integer
(b) lim x→a f(x) is non integer
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9 Answers
ksin2x + 1ksin2x = 2
As k>0, we have x+1/x=2
i.e. ksin2x = 1
=> sin2x = 1/k
So u can obtain the result
Ques2 was given in the book as
2) ) If lim x→a f(x) = lim x→a [f(x)] (where[.] denotes the greatest integral function) and f(x) is non constant continous function, then
(a) lim x→a f(x) is integer
(b) lim x→a f(x) is non integer
(c) f(x) has local maximum at x=a
(d) f(x) has local minima at x=a.
And the asn given was (a), (b)
I wonder why these questions are supposed to be only for the three of us. And obviously you need to change your book.
yeah.. there are a few really good guys here... Why have these questions to be for us alone :)
and the book has a typing error.. I wouldnt exactly say what anant sir has said.. but yeah you have to be careful when using the book.. This question for instance is a decent question :) (only the answer is incorrect)
Ans of second ques is only (a) lim x→a is integer
@Nishant sir, yes there was some printing error.