range

find the range of-
[x2] - [x]2

7 Answers

49
Subhomoy Bakshi ·

is the answer R = {n: n ε I - m2 ; m ε W}

I=(-∞,∞) W=[1,∞)

49
Subhomoy Bakshi ·

that is i mean to say all integers except perfect squares!!!

1
Hodge Conjecture ·

ans. is R

1
Hodge Conjecture ·

see i tried in this way.....

x = I + f
where I= integral part
f= fractional part
so...
[ (I+f)2 ] - I2

so f(x) comes out to be [f2 + 2If]

don't know how to proceed from here.......

49
Subhomoy Bakshi ·

Case I::

x≥0

suppose in the interval [n,n+1)

x2 ε [n2,(n+1)2)

[x2] ε {n2, n2+1, n2+2.....(n+1)2-1}

[x]=n

[x]2=n2

[x2]-[x]2 ε {0,1,2,.....2n}

Case II:

x<0

x ε [-n,-(n-1))

x2 ε ((n-1)2,n2]

[x2] ε {(n-1)2,(n-1)2+1...n2}

[x] = -n

[x]2=n2

[x2]-[x]2={-2n+1,-2n+2....0}

oops!!

seemingly now the range is coming R= I!! (ie -∞ to +∞ all integers!!!)

49
Subhomoy Bakshi ·

hey...it can never be R...

look thats because both the terms in the given function is an integer so the range can never be a non-ineger...

the best choice is what i got in second attempt...i.e. I

in the first attempt i was nt using any pen/paper and so got erronous results!!

1
Hodge Conjecture ·

u r rite..... ans. can't be R.....it has to be intergers ....

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