u r rite..... ans. can't be R.....it has to be intergers ....
7 Answers
is the answer R = {n: n ε I - m2 ; m ε W}
I=(-∞,∞) W=[1,∞)
see i tried in this way.....
x = I + f
where I= integral part
f= fractional part
so...
[ (I+f)2 ] - I2
so f(x) comes out to be [f2 + 2If]
don't know how to proceed from here.......
Case I::
x≥0
suppose in the interval [n,n+1)
x2 ε [n2,(n+1)2)
[x2] ε {n2, n2+1, n2+2.....(n+1)2-1}
[x]=n
[x]2=n2
[x2]-[x]2 ε {0,1,2,.....2n}
Case II:
x<0
x ε [-n,-(n-1))
x2 ε ((n-1)2,n2]
[x2] ε {(n-1)2,(n-1)2+1...n2}
[x] = -n
[x]2=n2
[x2]-[x]2={-2n+1,-2n+2....0}
oops!!
seemingly now the range is coming R= I!! (ie -∞ to +∞ all integers!!!)
hey...it can never be R...
look thats because both the terms in the given function is an integer so the range can never be a non-ineger...
the best choice is what i got in second attempt...i.e. I
in the first attempt i was nt using any pen/paper and so got erronous results!!