f(x)=(x-p)8(x-q)16
p not equals to q
then how many real roots possible for f(x)?
and please explain wat is the root repeated and how many times it repeated.
please give me ur explanation.
106maybe VERY wrong but.....
my guess, real roots are just 2 i.e. p and q if both p and q are real.
x=p is root repeated 8 times and x=q is root repeated 16 times.
consider (x-p)8(x-q)16=0
as it is already in factorised form, the roots are.........
(x-p)(x-p)...8 times*(x-q)(x-q).... 16 times
and as the degree of polynomial is 24 hence 8 roots are p and 16 are q
1ashish 's solution seems very correct to me
see the function will always be positive or zero (at p and q)
i never quite understood what "repeated roots" mean but ashish is quite convincing in what he says.
anyone who can point any mistake in this??
