Differentiating,
f'(x)=nxn-1+p
It has only one real root for n even and at the most two roots for n(>3) even
How many real roots does function f(x)=xn+px+q can have for n even and n odd(>3)
Differentiating,
f'(x)=nxn-1+p
It has only one real root for n even and at the most two roots for n(>3) even
One more way of thinking could be graph..
graph of x^n and graph of -px-q
see how many ponts they could intersect ;)