Thank u bhaiyyas.
How many real roots does function f(x)=xn+px+q can have for n even and n odd(>3)
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6 Answers
injun joe
·2009-09-04 23:48:02
Differentiating,
f'(x)=nxn-1+p
It has only one real root for n even and at the most two roots for n(>3) even
Lokesh Verma
·2009-09-05 02:30:49
One more way of thinking could be graph..
graph of x^n and graph of -px-q
see how many ponts they could intersect ;)