=> ∫xsinxcos2(sin xcos x- x)2
=> ∫xsinx(sinx-xcosx)2
Put sin x- xcosx = t
dt= xsinx dx
=> ∫ dtt2
=> -1sin x-xcosx +C
Hence option B is correct O.O o.O
- Soumyadeep Basu Yes, b is correct.Upvote·0· Reply ·2013-08-16 23:19:10
- Aakash Choudhary Yes b is correct one...