2 Answers
Lokesh Verma
·2009-05-23 00:33:36
xp yq = ( x+y )p+q
IN these questions there are two approaches.. either differentiate directly or differentiate after taking log
The second one is generally easier
take log on both sides
p log x + q log y = (p+q) Log (x+y)
differentiate
p/x+ q/y dy/dx = (p+q)/(x+y) {1+dy/dx}
Now can you find dy/dx?