1 Answers
Honey Arora
·2009-05-23 00:53:21
xp yq = ( x+y )p+q
Taking log on both the sides
p log x+q log y=(p+q)log(x+y)
Taking derivative
(dy/dx)[(q/y)-(p+q/x+y)]=(p+q/x+y)-p/x
solving
dy/dx=y/x