1don't you think it would be tedious to do that and then cancelling the terms ....i think taking log first and then differentiating will help...
4 Answers
39px^{p-1}y^{q}+x^{p}qy^{q-1}\frac{dy}{dx}=(p+q)(x+y)^{p+q-1}(1+\frac{dy}{dx})
now i think u can rearrange the terms to get \frac{dy}{dx}
1
1just take log and do naa.........u'll get..........
plogx*qlogy=(p+q)log(x+y)
u'll get remaning by differentiating.........
