11thanx bhaiyya
ƒ : R → R is a twice diffentiable fn. such that
Æ’'(x) = Æ’(1-x) for all x \epsilon R
Given Æ’(0) = 1 , Find Æ’(1)
(A) e - 2 (B) ln 2 - 1 (C) sec 1 + tan 1 (D) cos 1 + sin 1
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12 Answers
11o..thanx bhaiyya...BUT i've done this...and in the same way......this was for others to try !!!
21ek dbt tha : wud this f''(x)=-f'(1-x)=-f(x) not be f''(x)=-f'(1-x)=-f(-x)
Oh sorry did a mist in the signs ....... its perfect ...........
11@manish bhaiyya......
a sincere request : pls delete ur post so that others may try.
11rkish
HINT USE THE BASIC DEFINITION OF DIFFERENTIATION
f'(x)=\lim_{h\rightarrow 0}f(x+h)-f(x)/h
and also use the fact that
f"(x)=-f'(1-x)=-f(x)
I HOPE U COULD DO THIS 1 NOW !!!!!!!!!!!!!
11arrey bhai.....see post #2 !!!!
btw...thanx.
Pls proceed and get the ans.
11Æ’'(x) = Æ’(1-x)
f(0) = 1
Æ’'(0) = 0
Therefore f(1) = 0
Therefore B) is the answer
11@virang....
Did not understand :
i) Æ’'(0) = 0 [7][7][7]
ii) Therefore B) is the answer [7][7][7]
11Its given f(0)=1
Differentiating the function
f`(0) = 0
I think this is a method tell me if my method is wrong