itz simple bt mah ansewr is nt matchin
logx (y)=e^2x
dy/dx(logx)+1/x(dy/dx)=2e^2x
nw wen x=e y=e^2e substitue 4 it u'll get d ansewr
find dy/dx at x=e, y=e2x/logx
a) (e-1)e2e/e
b) o
c) 1
d) (e2-1)e2e/e
plz gv itz soln also
itz a ques from some test here bt i cldn't solve it,so plz help.....................
srry itz derivatives actually...........:)
itz simple bt mah ansewr is nt matchin
logx (y)=e^2x
dy/dx(logx)+1/x(dy/dx)=2e^2x
nw wen x=e y=e^2e substitue 4 it u'll get d ansewr
u r doing it wrong
thr is mistake in ur 2nd step
logx (y)=e^2x
=>dy/dx(logx)+(1/x)y=2e^2x