Simple ques on integration

VITEEE Guidance › Calculus questions › Simple ques on integration

find dy/dx at x=e, y=e^2x/logx
a) (e-1)e^2e/e
b) o
c) 1
d) (e²-1)e^2e/e
plz gv itz soln also
itz a ques from some test here bt i cldn't solve it,so plz help.....................
srry itz derivatives actually...........:)

#Mathematics #Calculus

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7 Answers

1

Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-02-07 10:05:00

r u shoore of d options m gettin an xtra 2 in d answer sumwer

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1

moon ·2009-02-07 10:15:13

ys these r the only options

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1

Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-02-07 10:26:56

itz simple bt mah ansewr is nt matchin
logx (y)=e^2x
dy/dx(logx)+1/x(dy/dx)=2e^2x

nw wen x=e y=e^2e substitue 4 it u'll get d ansewr

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1

moon ·2009-02-07 10:38:22

u r doing it wrong
thr is mistake in ur 2nd step
logx (y)=e^2x
=>dy/dx(logx)+(1/x)y=2e^2x

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1

moon ·2009-02-07 10:38:54

anyways thx,.........nd nw u'll also get the right ans

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21

tapanmast Vora ·2009-02-07 11:14:25

wats da ans???

is it a??????//

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11

Subash ·2009-02-07 18:53:37

im getting e^2e/e(2e-1)

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Your Answer

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