Solve the following limits - 2

8) d;
9) c;
10)b;
11) b;
12) 3;
13) 1;
For 14) the general term in the denominator is 4r² +3.on simplyfying the equation reduces to tan^-1(r+1/2) - tan^-1(r-1/2).Now after summing the term remaining is Ï€/2 - tan^-1(1/2),which is also equal to Ï€/4+Ï€/4-tan^-1(1/2).now calculate by taking one Ï€/4 as tan^-1(1).

8 is D
9 is C
10 is C
11 is B

12 is "zero"
13 is "one"