EASY!!!
each term within tan inv is of da form : [(x+n) - (x+n-1)]/[1+(x+n)(x+n-1)]
this is telescopic form....
ho gaya naa!!!
1/(x2+x+1)
= (x+1)-x
__________
1+x(x+1)
so it gives tan-1a - tan -1b formula...
if u do this for the whole sumation, you will get tan-1(x+n) - tan-1 x
now it is one step. :)
EASY!!!
each term within tan inv is of da form : [(x+n) - (x+n-1)]/[1+(x+n)(x+n-1)]
this is telescopic form....
ho gaya naa!!!