21
tapanmast Vora
·2009-03-08 04:54:32
INTEGRATION by parts........
take 1 as da integrable functn
11
virang1 Jhaveri
·2009-03-08 04:59:52
Please post the solution it is quite complicated
13
ДвҥїÑuÏ now in medical c
·2009-03-08 05:00:49
first.... take x=z2
then INTEGRATION by parts
11
virang1 Jhaveri
·2009-03-08 05:03:24
@Abhirup
Please solve it is a challenge not a doubt
13
ДвҥїÑuÏ now in medical c
·2009-03-08 05:13:27
2∫ztan-1z dz
=tan-1z*z2/2 - 1/2∫z2/(1+z2)dz
do this part ∫z2/(1+z2)dz
=∫(1+z2 ) dz /1+z2 -∫dz/1+z2
11
Mani Pal Singh
·2009-03-08 05:25:26
Virag
tunne kya hamein bevakoof samajh rakha hai
∂x KAHAN GAYA[7]