1Is the answer to the question is 3 ??
8 Answers
11dy/dx = y + 1.
integrating,
y = yx + x + c, where c is constant.
putting x = 0 we get,
y = c, but y =1 at x=0 (given)
c=1.
therefore, y = yx + x + 1.
=> y = (x + 1)/(1 - x).
at x= ln2
y = (ln2 + 1)/(1 - ln2)
11sorry i was damn wrong there....
i didn't pay heed to that y..
dy/dx = y+1.
dy/(y+1) = dx.
integrating,
=> ∫dy/(y+1) =∫dx.
=> ln(y+1) = x + c.
at x=0 and y=1, we get,
c = ln2
thus ln(y+1) = x + ln2
therefore, at x=ln2..
ln(y+1) = 2ln2 = ln4.
therefore y=3.
