verify..

f(x)= [sinx + cosx]
[.]=box function...

how many points of discontinuities when x belongs to (0, 2 pi) .. ??

me getting 5...
nyone verify....

2 Answers

answer should be 5.
in (0,2Ï€) sin(x)+cos(x) ranges from -âˆš2 to +âˆš2, so the func. attains value=1,0,-1,-2,-1,0. points in between are 5.

yup
right...
me too got this...
by the way, ans given is 6... (may be wrong..)

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