According to what I had said
(a2-1/2)2 = a4+1-2a2/4
(a2+1/2)2 = a4+1+2a2/4
(a2-1/2)2+a2= a4+1-2a2/4+a2
=a4+1+2a2/4 =(a2+1/2)2
Here is a very good trick to find a pythagorian triplet:
1.Square a number.
2.Add 1 to that number and subtract 1 from it
3.Divide the two numbers by 2
4.All the three numbers will give you a pythagorian triplet
For eg:
1. 52=25
2. ( i) 25+1=26 (ii) 25-1=24
3. (i) 26/2 =13 (ii) 24/2=12
4. The numbers are 5,12,13.
According to what I had said
(a2-1/2)2 = a4+1-2a2/4
(a2+1/2)2 = a4+1+2a2/4
(a2-1/2)2+a2= a4+1-2a2/4+a2
=a4+1+2a2/4 =(a2+1/2)2
gud work....
tell me how to get triplets of (6,8,10) and (10,24,25)....:)
You can get it in the same way!!
no matter if decimal comes.
Use a calc and check
well actually this formula is just an emperical relation b/w pythagorean triplets. moreover it is not satisfied by all the pythagorean triplets that exist rather it just gives a part of the whole story. Anyone interested in more such relations check out this page
http://www.larryhammer.com/pythagomath.html