then
\frac{2}{log_{4}(2000)^{6}}+\frac{3}{log_{5}(2000)^{6}}
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3 Answers
Lokesh Verma
·2010-12-21 10:46:09
then 2 log 4/ (6 log 2000) + 3 log 5 / (6 log 2000) = log(4^2.5^3)/ 6 log 2000 = 1/6