OL = √OB 2 - BL2
= √(2√3)2 - √(3)2
=√12-3
= 3 cm
circumference = (6 * pai) cm
Area = (9 * pai) cm2
A circle is inscribed in a regular hexagon of side 2√3cm.Find (i) circumference of the inscribed circle.
(ii)area of the inscribed circle.
.
OAB is equilateral triangle.
AB is given, find OL which is the radius of the circle
OL = √OB 2 - BL2
= √(2√3)2 - √(3)2
=√12-3
= 3 cm
circumference = (6 * pai) cm
Area = (9 * pai) cm2