Question is absolutely wrong........!!
Quadrilateral ABCD has AB=BC=CD, ANGLE ABC=70degees ,and ANGLE BCD=170degree.WHAT IS THE MEASURE OF ANGLE BAD?
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7 Answers
oishitmitra
·2011-08-23 06:19:46
yes Aritra...u r absolutly wrong...try working out the problem urslf...u will understand..
rahul
·2011-08-25 15:55:35
sorry bhai...!! Actually at that time i was a dumbo...
I just joined AC and BD
and thus assigned the angles
Consider Triangles ACD and ABD
From triangle ABD
r/sin(60° - Θ) = q/sin65° ---- (i)
and from triangle ACD
r/sinΘ = q/sin115° ---- (ii)
dividing (i) by (ii) we get,
sinΘ/sin(60°-Θ) = sin115°/sin65°
or, sinΘ = sin(60°-Θ)
as Θ<90° so, Θ = 30°
Thus, LBAD = 55° + 30° = 85°
Sambit Senapati
·2011-08-26 04:48:16
@rahulmishra-You were the one who said the question is wrong, right?