QUESTION

IF THE BISECTORS OF ANGLES,<ABC AND ACB OF A TRIANGLE ABC MEET AT POINT O THEN SHOW THAT <BOC =90+1/2<BAC.
HELP IN SOLVING IT!

1 Answers

Angle OBC = 1/2 B

< OCB = 1/2 C

< BOC = 180-(< OBC+< OCB) = 180 - (1/2(B+C)) = 180 - 1/2(180-A) = 90+A/2

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