Sayantan Sir, Please 'HELP ME'

If 2^x=3^y=6^-z,then what is the value of 1/x+1/y+1/z? How should I do this ?

4 Answers

206

Sayantan Hazra ·2013-08-10 03:25:37

Let 2^x = 3^y = 6^-z = k

Now try to find k^{1/x + 1/y + 1/z}

I have got 1/x+1/y+1/z=0. Is this correct?

UP 0 DOWN 1
Saptarshi Halder I have got 1/x+1/y+1/z=0. Is this correct?
Upvote·0· Reply ·2013-08-10 03:50:17
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206

Sayantan Hazra ·2013-08-10 04:10:51

Yes......absolutely :)

k^1/x+1/y+1/z
=k^2*3*1/6
=k¹

so,1/x+1/y+1/z=1.
I GOT 1.IS IT WRONG?

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Sayantan Hazra Yes, it is wrong.......how did you put (1/x) = 2 ??? and similarly the values of 1/y and 1/z ??
Upvote·0· Reply ·2013-08-11 09:44:02
Rohit Ghosh I ADMIT MY GUILT.
Upvote·0· Reply ·2013-08-15 00:41:00
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