31The first one is 3 might have been a problem while uploading.
For question 8 you are right it is 3X10^6 m thus 3X10^3 km
for 9 glance angle of incidence = 90-angle of incidence.
10. you are correct.... while entering v and u got interchanged...
How many images will be formed when two mirrors are kept perpendicular??
5
7
2
3
Your Answer
d
Correct Answer
b
how it is possible?MY WAS 3.
8)Find the distance traveled by light in 0.01 seconds in km
3X10^5
3X10^10
3X10^7
3X10^6
Your Answer
d
Correct Answer
c
the options are given wrong my ans.was3*103
9)If the angle of incidence is 30 then what is the glance angle of reflection?
30
60
90
depends on angle of reflection
Your Answer
a
Correct Answer
b
what is glance angle of reflection?
10)If f= 20 and v= 30 then u?
15
30
12
14
Your Answer
Not Attempted
Correct Answer
c
my ans. had come u=-60 according to the formula 1/f=1/v-1/u
WHAT ABOUT MY MARKS?
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UP 0 DOWN 0 0 5
5 Answers
69Your answer for the first question is absolutely correct. 360 degrees/angle in which the two mirrors are kept -1 = 360/90 -1 = 4-1 = 3
313YOUR FIRST ANSWER IS CORRECT .
THE FORMULA IS 360°/X-1 . SO, AS IT HAS BEEN KEPT PERPENDICULAR TO EACH OTHER IT SHOULD BE 90° . SO,
360°/90° - 1 IS 3 . SO , YOUR ANSWER IS CORRECT . YOU SHOULD DESERVE FULL MARKS .
3YOUR FIRST ANSWER IS CORRECT .
THE FORMULA IS 360°/X-1 . SO, AS IT HAS BEEN KEPT PERPENDICULAR TO EACH OTHER IT SHOULD BE 90° . SO,
360°/90° - 1 IS 3 . SO , YOUR ANSWER IS CORRECT . YOU SHOULD DESERVE FULL MARKS .
1For question 9 Glance angle of reflection = 90- angle of incidence
