Given
vi = 22.4 m/s
vf = 0 m/s
t = 2.55 s
the skidding distanceof the car (d)
d = (vi + vf)/2 *t
d = (22.4 m/s + 0 m/s)/2 *2.55 s
d = (11.2 m/s)*2.55 s
d = 28.6 m
A car traveling at 22.4m/s skids to a stop in 2.55s. Determine the skidding distance of the car (assume uniform acceleration).
Given
vi = 22.4 m/s
vf = 0 m/s
t = 2.55 s
the skidding distanceof the car (d)
d = (vi + vf)/2 *t
d = (22.4 m/s + 0 m/s)/2 *2.55 s
d = (11.2 m/s)*2.55 s
d = 28.6 m