POWER...

AIEEE Coaching › Class VII-X Physics questions › POWER...

an electric bulb rated 50W at 100V is used in a circuit having a 200V supply. What resistance R must be put in series with the bulb so that then bulb delivers 500W?

#Physics #Class VII-X Physics

UP 0 DOWN 0 0 4
Post on FacebookPost anonymously?

4 Answers

Pratyay Patra ·2014-01-24 06:25:38

TH ANSWER IS 10

UP 0 DOWN 0
Post on FacebookPost anonymously?

Pratyay Patra ·2014-01-24 06:25:41

TH ANSWER IS 10

UP 0 DOWN 1
Astha Gupta can u show how did u get dis answer?
Upvote·0· Reply ·2014-01-25 01:56:56
Post on FacebookPost anonymously?

Bunnie Boy ·2017-09-01 13:11:26

I=P/V

I=500/10=5A

Resistance of bulb,R1=100/5=20 ohm

Resistance,r to be connected in series,

5A=200/R1+R2

R1+R2=200/5

R1+R2=40

20+R2=40

R2=20 ohm

UP 0 DOWN 1
Anonymous I=500/100 instead of 500/10
Upvote·0·2017-09-01 13:14:03
Post on FacebookPost anonymously?

Bunnie Boy ·2017-09-01 13:12:41

This answer is for 500W not 50 W

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

POWER...

4 Answers

Your Answer

Add Image

Similar Questions